Question

Two 5 molal solutions are prepared by dissolving a non-electrolyte non-volatile solute separately in the solvents X and Y. The molecular weight of the solvents are $M_X$ and $M_Y$, respectively where $M_X=\frac{3}{4}{M}_Y$. The relative lowering of vapour pressure of the solution in X is "m" times that of the solution in Y. Given that the number of moles of solute is very small in comparison to that of solvent, the value of "m" is?

• A. $\frac{4}{3}$
• B. $\frac{3}{4}$
• C. $\frac{1}{2}$
• D. $\frac{1}{4}$

Answer 1

Answer: (B)