Let the two A.P's be a1,a2,a3,....,an,.... and b1,b2,b3,....bn,....
Also let the two common difference of two A.P's. Then,
an=a1(n−1)d and bn=b1+(n−1)d
⟹an−bn={a1+(n−1)d}−{b1+(n−1)d}
⟹an−bn=a1−b1
Clearly, an−bn is independent of n and is equal to a1−b1. In other words
an−bn=a1−b1 for all n∈N.
⟹a100−b100=a1−b1
and, ak−bk=a1−b1, where k=10,00,000
But, a100−b100=111222333
∴a1−b1=111222333
⟹ak−bk=a1−b1=111222333, where k=10,00,000.
Hence, the difference between millionth terms is same as the difference between 100th terms i.e., 111222333.