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Black-Body Radiation

Two absolute ...

Question

Two absolute scales A and B have triple points of water defined to be 200 A and 300 B (given triple point of water is $=$ 276.16 K). The relation between $T_{A}$ and $T_{B}$ is

T_{A} = T_{B}

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T_{B} = \frac{3}{2} T_{A}

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T_{B} = \frac{2}{3} T_{A}

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T_{B} = \frac{3}{4} T_{A}

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Solution

The correct option is C $T_{B} = \frac{3}{2} T_{A}$
Use the formula:
$\frac{(276.16) T_{A}}{200} = \frac{(276.16) T_{B}}{300}$
$∴ T_{B} = 1.5 T_{A}$

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Two absolute scales A and B have triple points of water defined to be 200 A and 350 B. What is the relation between T_A and T_B?

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