Two acids have been derived from H2O2 by replacing H by SO2OH group- Both the acids have one peroxy linkage H-O-O-H- H-O-H2SO5O-SO2-OH H-O-O-H- HO-SO2-H2S2O8O-O-SO2-OHBased on the above study- answer the following question-Which reacts with KMnO4-

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Stoichiometry

Two acids hav...

Question

Two acids have been derived from $H_{2} O_{2}$ by replacing $H$ by $(S O_{2} O H)$ group. Both the acids have one peroxy linkage

$H - O - O - H$ , $H - O - O - S O_{2} H_{2} S O_{5} - O H$

$H - O - O - H$ , $H O - S O_{2} - O - O - H_{2} S_{2} O_{8} S O_{2} - O H$

Based on the above study, answer the following question:

Which reacts with $K M n O_{4}$ ?

H_{2} S O_{3}

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H_{2} S O_{5}

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H_{2} S O_{4}

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H_{2} S_{2} O_{8}

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H_{2} O_{2}

H

(S O_{2} O H)

H - O - O - H

H - O - O - S O_{2} H_{2} S O_{5} - O H

H - O - O - H

H O - S O_{2} - O - O - H_{2} S_{2} O_{8} S O_{2} - O H

H_{2} S_{2} O_{8}

$H^{+}$ ions released by acids combine with water to form ______ ions.

S H^{-}, A c O^{-}, P h O^{-}, O H^{-}, H_{2} O

H_{2} O

H F

H - O | | C - O H I ⟷ H - O^{-} | C - + O I I ⟷ H - O | + C - O I I I ⟷ H - O | - C - O H V I

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