Two adjacent angles of a parallelogram are $(2 x + 25)^{\circ} a n d (3 x - 5)^{\circ}$ . The value of x is

(a) 28 (b) 32 (c) 36 (d) 42

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Solution

The sum of adjacent angles of a || gm = $180^{\circ}$

$∴ 2 x + 25^{\circ} + 3 x - 5^{\circ} = 180^{\circ}$

$\Rightarrow 5 x + 20^{\circ} = 180^{\circ}$

$\Rightarrow 5 x = 180^{\circ} - 20^{\circ} = 160^{\circ}$

$\Rightarrow x = \frac{160}{5} = 32^{\circ}$

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Two adjacent angles of a parallelogram are (2x+25)∘ and (3x−5)∘. The value of x is (a) 28 (b) 32 (c) 36 (d) 42

The sum of adjacent angles of a || gm = 180∘ ∴2x+25∘+3x−5∘=180∘ ⇒5x+20∘=180∘ ⇒5x=180∘−20∘=160∘ ⇒x=1605=32∘

Two adjacent angles of a parallelogram are $(2 x + 25)^{\circ} a n d (3 x - 5)^{\circ}$ . The value of x is

(a) 28 (b) 32 (c) 36 (d) 42

The sum of adjacent angles of a || gm = $180^{\circ}$

$∴ 2 x + 25^{\circ} + 3 x - 5^{\circ} = 180^{\circ}$

$\Rightarrow 5 x + 20^{\circ} = 180^{\circ}$

$\Rightarrow 5 x = 180^{\circ} - 20^{\circ} = 160^{\circ}$

$\Rightarrow x = \frac{160}{5} = 32^{\circ}$