Question

# Two adjacent angles of a parallelogram are in the ratio $$4:5$$, Find all the angles of the parallelogram

A
C=A=90o,D=B=100o
B
C=A=80o,D=B=100o
C
C=A=D=B=90o
D
None of above

Solution

## The correct option is B $$\angle C = \angle A = 80^o, \angle D =\angle B = 100^o$$Let $$ABCD$$ be a parallelogram.Given that, $$\angle A:\angle B=4:5$$Sum of the ratios $$=4+5=9$$But, $$\angle A+\angle B=180^o$$(Adjacent angles of the parallelogram, $$ABCD$$)$$\therefore \angle A=\dfrac {4}{9}\times 180^o=80^o$$$$\angle B=\dfrac {5}{9}\times 180^o=100^o$$So $$\angle C = \angle A = 80^o, \angle D =\angle B = 100^o$$(Opposite angles of a parallelogram are equal). Maths

Suggest Corrections

0

Similar questions
View More

People also searched for
View More