Question

Two adjacent angles of a parallelogram are ${\left(3x-4\right)}^{\circ }$ and ${\left(3x+16\right)}^{\circ }$. Find the measure of each of its angles.

Answer 1

$2(3x-4+3x+16)={360}^{\circ }$

$⟹6x+12={180}^{\circ }$

$⟹x+2={30}^{\circ }$

$⟹x={28}^{\circ }$

Hence, angles are ${80}^{\circ },{80}^{\circ },{100}^{\circ },{100}^{\circ }$