Question

Two adjacent angles of a rhombus are $3x-{40}^{\circ }$ and $2x+{20}^{\circ }$. The measurement of the greater angle is:

• A. ${160}^{\circ }$
• B. ${100}^{\circ }$
• C. ${80}^{\circ }$
• D. ${120}^{\circ }$

Answer 1

The correct option is B ${100}^{\circ }$

The sum of adjacent angles of a rhombus is ${180}^{\circ }$

$\therefore 3x-{40}^{\circ }+2x+{20}^{\circ }={180}^{\circ }$

Or, $x={40}^{\circ }$

So angles are $3x-{40}^{\circ }={80}^{\circ }$ and $2x+{20}^{\circ }={100}^{\circ }$