Two adjacent angles of rhombus are 3x-40- and 2x-20- Find the measure of the greater angle-

3x 40^∘+2x+20^∘=180^∘ nbsp; nbsp; nbsp; [Sum of adjacent angles of rhombus are equal to 180^∘.] 5x 20^∘=180^∘ 5x=180^∘+20^∘ 5x=200^∘ x=200/5=40^∘ ⇒ 3x 40^ ...

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Standard IX

Mathematics

Important Results Related to Parallelograms

Two adjacent ...

Question

Two adjacent angles of rhombus are $(3 x - 40)^{\circ} a n d (2 x + 20)^{\circ} .$ Find the measure of the greater angle.

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Solution

$3 x - 40^{\circ} + 2 x + 20^{\circ} = 180^{\circ}$ [Sum of adjacent angles of rhombus are equal to $180^{\circ}$ .]
$5 x - 20^{\circ} = 180^{\circ}$
$5 x = 180^{\circ} + 20^{\circ}$
$5 x = 200^{\circ}$
$x = \frac{200}{5} = 40^{\circ}$
$\Rightarrow 3 x - 40^{\circ} = 3 (40) - 40 = 80^{\circ}$
$\Rightarrow 2 x + 20^{\circ} = 2 (40) + 20 = 100^{\circ}$
The measure of the greater angle is $100^{\circ}$ .

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Two adjacent angles of rhombus are (3x−40)∘ and (2x+20)∘. Find the measure of the greater angle.

3x−40∘+2x+20∘=180∘ [Sum of adjacent angles of rhombus are equal to 180∘.] 5x−20∘=180∘ 5x=180∘+20∘ 5x=200∘ x=2005=40∘ ⇒3x−40∘=3(40)−40=80∘ ⇒2x+20∘=2(40)+20=100∘ The measure of the greater angle is 100∘.

Two adjacent angles of rhombus are $(3 x - 40)^{\circ} a n d (2 x + 20)^{\circ} .$ Find the measure of the greater angle.