Two adjacent sides of a parallelogram have lengths 12 cm and 8 cm. The distance between the two longer sides is 6 cm. Find the area of the parallelogram and the distance between the two shorter sides.

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Solution

Area of Parallelogram = Base $\times$ Height = $8 \times 6 = 48 {c m}^{2}$
So Distance between two shorter sides = $\frac{48}{12} = 4 c m$

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Two adjacent sides of a parallelogram have lengths 12 cm and 8 cm. The distance between the two longer sides is 6 cm. Find the area of the parallelogram and the distance between the two shorter sides.

Area of Parallelogram = Base × Height = 8×6=48 cm2So Distance between two shorter sides = 4812=4 cm

Area of Parallelogram = Base $\times$ Height = $8 \times 6 = 48 {c m}^{2}$
So Distance between two shorter sides = $\frac{48}{12} = 4 c m$