wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two adjacent sides of a rectangle are
−6x2+9y2−5xy and x2−2x+9xy.
Find its perimeter.

A
5x28xy9y2+2x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10x28xy18y2+4x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5x2+4xy+9y22x
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10x2+8xy+18y24x
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 10x2+8xy+18y24x
Given: Sides of a rectangle are 6x2+9y25xy and x22x+9xy.
The perimeter of the rectangle = 2(length + breadth)
P=2[(6x2+9y25xy)+(x22x+9xy)]
Grouping the like terms together,
P=2[(6x2+x2)+9y2+(5xy+9xy)2x]
P=2(5x2+4xy+9y22x)
P=10x2+8xy+18y24x

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Addition and Subtraction of Algebraic Expression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon