Two alloys, A and B, contain silver and copper in the ratio 5 : 1 and 7 : 2, respectively. Find the ratio in which they must be mixed such that there is 80% of silver.

3 : 2

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2 : 3

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1 : 3

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3 : 4

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None of these

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Solution

The correct option is B 2 : 3
Resulting alloy has 80% of silver and hence, 20% of copper.
$∴$ Silver:Copper =80:20 =4:1.
By Alligation rule,

$∴$ Required ratio = $\frac{1}{45} : \frac{1}{30}$
i.e., Type A:Type B = $\frac{1}{3} : \frac{1}{2} = 2 : 3.$

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Two alloys, A and B, contain silver and copper in the ratio 5 : 1 and 7 : 2, respectively. Find the ratio in which they must be mixed such that there is 80% of silver.

The correct option is B 2 : 3Resulting alloy has 80% of silver and hence, 20% of copper. ∴ Silver:Copper =80:20 =4:1. By Alligation rule, ∴ Required ratio =145:130 i.e., Type A:Type B =13:12=2:3.

The correct option is B 2 : 3
Resulting alloy has 80% of silver and hence, 20% of copper.
$∴$ Silver:Copper =80:20 =4:1.
By Alligation rule,

$∴$ Required ratio = $\frac{1}{45} : \frac{1}{30}$
i.e., Type A:Type B = $\frac{1}{3} : \frac{1}{2} = 2 : 3.$