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Question

# Two alloys, A and B, contain silver and copper in the ratio 5 : 1 and 7 : 2, respectively. Find the ratio in which they must be mixed such that there is 80% of silver.

A
3 : 2
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B
2 : 3
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C
1 : 3
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D
3 : 4
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E
None of these
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Solution

## The correct option is B 2 : 3Resulting alloy has 80% of silver and hence, 20% of copper. ∴ Silver:Copper =80:20 =4:1. By Alligation rule, ∴ Required ratio =145:130 i.e., Type A:Type B =13:12=2:3.

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