Question

Two alpha particles are separated by a distance of ${10}^{-13}m$. The force between them in free space is :

• A. $92.16\times {10}^{-3}N$
• B. $92.16\times {10}^{-4}N$
• C. $92.16\times {10}^{-5}N$
• D. $92.16\times {10}^{-2}N$

Answer 1

The correct option is A $92.16\times {10}^{-3}N$

$\alpha particlesareH{e}^{+2}ions$
$\therefore$ Net charge present on them is $2\times (1\cdot 6\times {10}^{-19})C.$
We know $F=\frac{k{q}_1{q}_2}{r^2}$

$F=\frac{(9\times {10}^9)(2\times 1\cdot 6\times {10}^{-19})(2\times 1\cdot 6\times {10}^{-19})}{({10}^{-13}{)}^2}$

$F=\frac{92\cdot 16\times {10}^{-29}}{{10}^{-26}}$

$F=92\cdot 16\times {10}^{-3}N$