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Resistance of P-N Junction

Two ammeters ...

Question

Two ammeters $A_{1}$ & $A_{2}$ are placed in the circuit above with the two resistors as shown, Identify which of the following statements is true about the reading of these ammeters?

A_{1} = A_{2}

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A_{1} > A_{2}

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A_{1} < A_{2}

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A_{1} = 0

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A_{2} = 0

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Solution

The correct option is E $A_{1} < A_{2}$
Given : $R_{1} = 10 Ω$ $R_{2} = 5 Ω$
Current through $R_{1}$ $I_{1} = \frac{V}{R_{1}} = \frac{V}{10}$

Current through $R_{2}$ $I_{2} = \frac{V}{R_{2}} = \frac{V}{5}$
Thus ammeter $A_{1}$ reads less current that ammeter $A_{2}$ .
Hence option C is correct.

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A_{1}, A_{2}, & A_{3}

a_{1} x^{2} + b_{1} x + c_{1} = 0, a_{2} x^{2} + b_{2} x + c_{2} = 0

a_{3} x^{2} + b_{3} x + c_{3} = 0

\frac{c_{1} a_{2} + c_{2} a_{1}}{c_{1} a_{2} - c_{2} a_{1}} + \frac{a_{1} a_{2} b_{3}}{a_{3} (a_{1} b_{2} - a_{2} b_{1})} = 0

{(\frac{a_{1} b_{2} - a_{2} b_{1}}{a_{1} c_{2} - a_{2} c_{1}})}^{2} = \frac{a_{1} a_{2} c_{3}}{c_{1} c_{2} a_{3}}

a_{1}, a_{2}, . . .

a_{1} \neq 0

a_{1}, a_{2}, a_{3}, . . .

A_{1}, a_{2}, . . . . . . .

a_{1} \neq 0

a_{1}, a_{2}, a_{3}, . . . . .

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