Question

Two and a half liters of paint are used to cover $725m^2$ of area. How much will be required to paint $2001m^2$ of area ?

Answer 1

Given, amount of paint required to cover an area of $725m^2=2.5$ ltr
Thus, the amount of paint required to cover an area of $1m^2=\frac{2.5}{725}$ ltr
Therefore, the amount of paint required to cover an area of $2001m^2=\frac{2.5}{725}\times 20001$
$=6.9$ ltr
Hence, $6.9$ ltr of paint required to paint $2001m^2$ area.