Question

Two angles are complementary. The larger angle is $3^0$ less than twice the measure of the smaller angle. Find the measure of each angle.

• A. ${51}^0$ , ${39}^0$
• B. ${22}^0$ , ${68}^0$
• C. ${31}^0$ , ${59}^0$
• D. ${42}^0$ , ${48}^0$

Answer 1

The correct option is C ${31}^0$ , ${59}^0$

$letlargeranglexandsmallerangleyx+y={90}^{\circ }andx=2y-3^{\circ }w.k.tx+y={90}^{\circ }or2y-3^{\circ }+y={90}^{\circ }3y-3^{\circ }={90}^{\circ }3y={93}^{\circ }y={31}^{\circ }thenx={90}^{\circ }-{31}^{\circ }={59}^{\circ }$