Question

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

Answer 1

Let the two equal angles are x°, then the third angle will be (x + 30)°.

$$\begin{gathered} \therefore x+x+\left(x+30\right)=180\left[\mathrm{Sum}\mathrm{of}\mathrm{the}\mathrm{three}\mathrm{angles}\mathrm{of}\mathrm{a}\mathrm{triangle}\mathrm{is}180°\right] \\ \Rightarrow 3x+30=180 \\ \Rightarrow 3x=150 \\ \Rightarrow x=50 \end{gathered}$$

Therefore, the angles of the given triangle are 50°, 50° and 80°.