Two angles of a triangle are in the ratio (23:32) and the third angle is 50∘. The two angles are:
A
30∘,95∘
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B
45∘,85∘
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C
30∘,100∘
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D
40∘,90∘
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Solution
The correct option is D40∘,90∘ Let the two angles of the triangle be 23xand32x ⇒23x+32x+50∘=180∘ ⇒4x+9x6=130∘ ⇒13x=130∘×6 ⇒x=780∘13=60∘. Now,23×60=40∘and32×60=90∘. Hence, the required angles are 40∘,90∘.