Two APs have the same common difference. The first term of one of these is −1 and that of the other is −8. Then the difference between their 4th terms is
A
−1
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B
−8
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C
7
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D
−9
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Solution
The correct option is C7 Let the same common difference of two A.P. be d First term of 1st AP =−1 Forth term of 1st AP =(−1+3d) First term of 2nd AP =−8 Forth term of 2nd AP =(−8+3d) Then (a4)1stAP−(a4)2ndAP=(−1+3d)−(−8+3d) =−1+3d+8−3d=7