Two APs have the same common difference. Their first terms are −1 and −8, respectively. The difference between their 4th terms is
(a) −1
(b) −8
(c) 7
(d) −9

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Solution

(c) 7

Let the common difference of each AP be d. Then we have:
T₄ = a + (n - 1)d = -1 + 3d
t₄ = a + (n - 1)d = -8 + 3d
∴ (T₄ - t₄) = (-1 + 3d) - (-8 + 3d) = 7
Hence, the difference between their 4^th terms is 7.

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Q. Question 11
Two APs have the same common difference. The first term of one of these is – 1 and that of the other is – 8. The difference between their

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A) -1
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Q. Two APs have the same common difference. If the first terms of these APs be 3 and 8 respectively, find the difference between the sums of their first 50 terms. [CBSE 2011]

Two APs have the same common difference. If the first terms of these APs be 3 and 8 respectively, find the difference between the sums of their first 50 terms.

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Two APs have the same common difference. Their first terms are −1 and −8, respectively. The difference between their 4th terms is (a) −1 (b) −8 (c) 7 (d) −9

(c) 7 Let the common difference of each AP be d. Then we have: T4 = a + (n - 1)d = -1 + 3d t4 = a + (n - 1)d = -8 + 3d ∴ (T4 - t4) = (-1 + 3d) - (-8 + 3d) = 7 Hence, the difference between their 4th terms is 7.

Two APs have the same common difference. Their first terms are −1 and −8, respectively. The difference between their 4th terms is
(a) −1
(b) −8
(c) 7
(d) −9

(c) 7

Let the common difference of each AP be d. Then we have:
T₄ = a + (n - 1)d = -1 + 3d
t₄ = a + (n - 1)d = -8 + 3d
∴ (T₄ - t₄) = (-1 + 3d) - (-8 + 3d) = 7
Hence, the difference between their 4^th terms is 7.