Two arcs APB and CQD of a circle are in the ratio 15 :7. The angle subtended by arc CQD at the centre is $105^{o}$ . Find the angle subtended by arc APB at the centre of the circle ?

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Solution

arc APB : arc CQD = 15:7
the angle subtended by them at the centre is also in the ratio 15:7 (1 mark)

$∴$ The angle subtended by arc APB at the centre is $\frac{15}{7} \times 105^{o} = 225^{o}$ (1 mark)

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Two arcs APB and CQD of a circle are in the ratio 15 :7. The angle subtended by arc CQD at the centre is 105o. Find the angle subtended by arc APB at the centre of the circle ?

arc APB : arc CQD = 15:7 the angle subtended by them at the centre is also in the ratio 15:7 (1 mark) ∴ The angle subtended by arc APB at the centre is 157 × 105o = 225o (1 mark)

Two arcs APB and CQD of a circle are in the ratio 15 :7. The angle subtended by arc CQD at the centre is $105^{o}$ . Find the angle subtended by arc APB at the centre of the circle ?

arc APB : arc CQD = 15:7
the angle subtended by them at the centre is also in the ratio 15:7 (1 mark)

$∴$ The angle subtended by arc APB at the centre is $\frac{15}{7} \times 105^{o} = 225^{o}$ (1 mark)