Two arcs APB and CQD of a circle are in the ratio 5 :7. The angle subtended by arc APB at the centre is $150^{o}$ .

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Solution

The correct option is A
1

arc APB : arc CQD = 5 : 7

$∴$ The angle subtended by arc APB at the centre is $\frac{5}{12} \times 360^{o} = 150^{o}$

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Similar questions

Two arcs APB and CQD of a circle are in the ratio 5 :7. The angle subtended by arc CQD at the centre is ___ degrees

O is the centre of the circle. AB is a minor arc of the circle. The angle subtended by AB at centre, $∠$ AOB = $110^{\circ}$ , then angle subtended by the arc at any point on the circle say $∠$ APB is ____, where P is any point on the circle.

O is the centre of the circle. AB is a minor arc of the circle. The angle subtended by AB at centre $∠$ AOB = $110^{\circ}$ , then angle subtended by the arc at any point on the remaining part of the circle i.e. $∠$ APB is (where P is any point on the circle)?

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[P is any point on the circle]

Q. If the arc length and the circumference of a circle are in the ratio

1 : 5

, find the angle subtended by the arc at the centre.

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Two arcs APB and CQD of a circle are in the ratio 5 :7. The angle subtended by arc APB at the centre is 150o.

The correct option is A 1 arc APB : arc CQD = 5 : 7 ∴ The angle subtended by arc APB at the centre is 512 × 360o = 150o

Two arcs APB and CQD of a circle are in the ratio 5 :7. The angle subtended by arc APB at the centre is $150^{o}$ .

The correct option is A
1

arc APB : arc CQD = 5 : 7

$∴$ The angle subtended by arc APB at the centre is $\frac{5}{12} \times 360^{o} = 150^{o}$