Two army persons A and B each of weight $500 N$ climbs up a rope through a height of 10 m. A takes 20 sec, while B takes 40 sec to achieve this task. What is the ratio of powers of person A and B?

1:2

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1:4

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2:1

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14:1

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Solution

The correct option is C $2:1$
$Power = \frac{W}{t} = \frac{F . S}{t}$
$given, F_{A} = 500 N, F_{B} = 500 N,$
$t_{A} = 20 sec,$ $t_{B} = 40 sec,$
$s = 10 m$
$\frac{P_{A}}{P_{B}} = \frac{F_{A} . S}{t_{A}}$ $\frac{t_{B}}{F_{B} . S}$
$\frac{P_{A}}{P_{B}} = \frac{500 \times 40}{20 \times 500} = \frac{2}{1}$

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Two army persons A and B each of weight 500 N climbs up a rope through a height of 10 m. A takes 20 sec, while B takes 40 sec to achieve this task. What is the ratio of powers of person A and B?

The correct option is C 2:1Power=Wt=F.St given, FA=500 N, FB=500 N, tA=20 sec, tB=40 sec, s=10 m PAPB=FA.StAtBFB.S PAPB=500×4020×500=21

Two army persons A and B each of weight $500 N$ climbs up a rope through a height of 10 m. A takes 20 sec, while B takes 40 sec to achieve this task. What is the ratio of powers of person A and B?