Question

Two bags contain ten coins each and the coins in each bag are numbered from 1 to 10, one coin is drawn at random from each bag. The probability that one of the coin has value 1, 2, 3 or 4 while the other has value 7, 8, 9 or 10 is _____________.

• A. 0.32

Answer 1

The correct option is A 0.32
Probability $\left(P_1\right)$ for taking any of number (1, 2, 3, 4) from bag 1 and (7, 8, 9, 10) from bag 2

$P_1=\frac{4}{10}\times \frac{4}{10}=0.16$

Similary probability $\left(P_2\right)$ for taking any of number (7, 8, 9, 10) from bag 1 and (1, 2, 3, 4) from bag 2

$P_2=\frac{4}{10}\times \frac{4}{10}=0.16$

Overall probability to draw the coins is equal to

$P_T=P_1+P_2=0.16+0.16=0.32$