Two balance disc are rolled. Find the probability that the sum of numbers on two disc is a multiple of $5$ .

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Solution

Total out comes $= 6 \times 6$

favourable out comes $= (1, 4) (2, 3) (3, 2) (4, 1) (5, 5) (6, 4) (4, 6)$

$= 7$

Probability $= \frac{7}{36}$

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Two balance disc are rolled. Find the probability that the sum of numbers on two disc is a multiple of 5.

Total out comes =6×6 favourable out comes =(1,4)(2,3)(3,2)(4,1)(5,5)(6,4)(4,6) =7Probability =736

Two balance disc are rolled. Find the probability that the sum of numbers on two disc is a multiple of $5$ .

Total out comes $= 6 \times 6$

favourable out comes $= (1, 4) (2, 3) (3, 2) (4, 1) (5, 5) (6, 4) (4, 6)$

$= 7$

Probability $= \frac{7}{36}$