Question

Two balls A and B are projected simultaneously as shown in the figure. Find the closest distance between the balls.

A
30 m
B
50 m
C
60 m
D
80 m

Solution

The correct option is B 50 m∵ Relative acceleration between the balls is zero. ∴ Bodies are moving with constant velocities w.r.t each other. Considering B to be at rest and finding −−→VAB velocity of A w.r.t B. −−→VAB=(20+20sin30∘)^i+(20cos30∘)^j⇒VAB=30^i+10√3^j and the angle made with the horizontal is tanθ=10√330⇒θ=30∘ Shortest distance between the balls BC=ABsin30∘=100(12)=50 m Hence option B is the correct answerPhysics

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