Two balls A and B are projected simultaneously as shown in the figure. Find the closest distance between the balls.
The correct option is B50m ∵ Relative acceleration between the balls is zero. ∴ Bodies are moving with constant velocities w.r.t each other. Considering B to be at rest and finding −−→VAB velocity of A w.r.t B.
−−→VAB=(20+20sin30∘)^i+(20cos30∘)^j⇒VAB=30^i+10√3^j and the angle made with the horizontal is tanθ=10√330⇒θ=30∘
Shortest distance between the balls BC=ABsin30∘=100(12)=50m