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Question

Two balls A and B are projected simultaneously as shown in the figure. Find the closest distance between the balls.


A
30 m
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B
50 m
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C
60 m
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D
80 m
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Solution

The correct option is B 50 m
Relative acceleration between the balls is zero.
Bodies are moving with constant velocities w.r.t each other.
Considering B to be at rest and finding VAB velocity of A w.r.t B.

VAB=(20+20sin30)^i+(20cos30)^jVAB=30^i+103^j and the angle made with the horizontal is
tanθ=10330θ=30

Shortest distance between the balls BC=ABsin30=100(12)=50 m

Hence option B is the correct answer

Physics

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