You visited us 4 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Physics

Derivation of Position-Time Relation by Graphical Method

Two balls A...

Question

Two balls $A$ and $B$ are simultaneously thrown. $A$ is thrown from the ground level with a velocity of $20 m s^{- 1}$ in the upward direction and $B$ is thrown from a height of $40 m$ in the downward direction with the same velocity. Where will the two balls meet?

15 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $15 m$
Let both the ball meet after time $t$ and $x$ be the distance covered by ball $A$ .
So $, x = 20 t - \frac{1}{2} (10) t^{2} . . . (1)$
For ball $B, (40 - x) = 20 t + \frac{1}{2} (10) t^{2} . . . (2)$
Adding $(1) & (2), 40 = 40 t o r t = 1 s$
so $x = 20 - 5 = 15 m$

Suggest Corrections

Similar questions

Two balls

A

and

B

are thrown with same velocity

u

from the top of a tower Ball

A

is thrown vertically upward and the ball

B

is thrown vertically downward. Choose the correct statement.

Q. A body is dropped from a

100 m

high eliff and at the same time another body is thrown from the ground with

25 m / s

velocity in upward direction. Where the two will meet?

Q. Two bodies

A

and

B

are thrown simultaneously.

A

is projected vertically upwards with

20 m/s

speed from the ground and

B

is projected vertically downwards from a height of

40 m

at the same speed and along the same line of motion. At what point do the two bodies collide?

(g = 10 {m/s}^{2})

Q. Two balls are thrown simultaneously,

(A)

vertically upwards with a speed of

20 m / s

from the ground and

(B)

vertically downwards from the height of

40

m

with the same speed and along the same line of motion. At which points the balls will collide? (take

g = 10 m / s^{2}

)

two balls A and B are thrown simultaneously vertically upwards with a speed of 20 metre per second from the ground and the downwards s from a height of 40m with the same speed and along the same line of motion at what point does the ball collide?

Join BYJU'S Learning Program

Two balls A and B are simultaneously thrown. A is thrown from the ground level with a velocity of 20 ms−1 in the upward direction and B is thrown from a height of 40 m in the downward direction with the same velocity. Where will the two balls meet?

The correct option is B 15 mLet both the ball meet after timet and x be the distance covered by ball A.So, x=20t−12(10)t2...(1)For ball B,(40−x)=20t+12(10)t2...(2) Adding (1) & (2),40=40tort=1 s so x=20−5=15 m

Two balls $A$ and $B$ are simultaneously thrown. $A$ is thrown from the ground level with a velocity of $20 m s^{- 1}$ in the upward direction and $B$ is thrown from a height of $40 m$ in the downward direction with the same velocity. Where will the two balls meet?

The correct option is B $15 m$
Let both the ball meet after time $t$ and $x$ be the distance covered by ball $A$ .
So $, x = 20 t - \frac{1}{2} (10) t^{2} . . . (1)$
For ball $B, (40 - x) = 20 t + \frac{1}{2} (10) t^{2} . . . (2)$
Adding $(1) & (2), 40 = 40 t o r t = 1 s$
so $x = 20 - 5 = 15 m$