Two balls A and B of same size are dropped from the same point under gravity. The mass of A is greater than that of B. If the air resistance acting on each ball is same, then:
A
both the balls reach the ground simultaneously
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B
the ball A reaches earlier
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C
the ball B reaches earlier
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D
nothing can be said
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Solution
The correct option is B the ball A reaches earlier Since the air resistance is same thus they have same forces acting on them (air resistance and gravity). The force equation for masses A and B will be MAg−R=MA×aA...(i) MBg−R=MB×aB...(ii) where R is air resistance force and,g is acceleration due to gravity. aA=g−RMAaB=g−RMB MA>MB⇒aA>aB