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Question

Two balls are dropped from different heights at different instants. Second ball is dropped 2 sec after the first ball. If both balls reach the ground simutlanously after 5 sec of dropping the first ball, the difference of initial heights of the two balls will be: (g=9.8 m/s2)

A
58.8m
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B
78.4m
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C
98.0m
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D
117.6m
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Solution

The correct option is A 78.4m
h1h2=12g(t21t22)
=12×9.8[(5)2(3)2]
=8×9.8 =78.4m

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