Two balls of equal masses are projected upward simultaneously, one from the ground with speed 50m/s and other from a 40m high tower with initial speed 30m/s. Find the maximum height attained by their centre of mass.
A
100 m
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B
200 m
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C
150 m
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D
50 m
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Solution
The correct option is A 100 m VCM=m1v1+m2v2m1+m2=(v1+v2)/2 Initially,UCM=40m/sXCM=40/2=20maboveground.MaximumheightmeansVCM=0Thatis,02−402=2×(−10)×(H−20)ThusH=100m