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Question

# Two balls of equal masses are thrown upwards, along the same vertical direction at an interval of 2 seconds, with the same initial velocity of 40m/s. Then these collide at a height of (Take g=10m/s2).

A
120m
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B
75m
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C
200m
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D
45m
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Solution

## The correct option is C 75mLet the two balls collide t sec after the first ball is thrown, and let h be the height at which they collide.For the first ball: h=40t−12gt2And for the second ball:h=40(t−2)−12g(t−2)240t−12gt2=40(t−2)−12g(t−2)22gt=80+20=100t=5 sec∴h=40×5−12×10×52=75mHence, option B is correct.

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