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Question

Two balls of masses 1 kg each are attached with two strings each of length 1 m as shown in figure. They are rotated in a horizontal circle with angular speed ω=4 rad/s about point 'O'. The ratio of tensions T1T2 is:


A
32
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B
23
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C
4
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D
14
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Solution

The correct option is A 32
Given mA=1 kg;mB=1kg
rA=length of mA from 'O'=1 m
rB=length of mB from 'O'=2 m

FBD considering only horizontal forces, because vertical forces balance each other i.e N=mg:


Applying equation of circular motion along radial direction for mB and mA respectively:
T2=mBrBω2=1×2×42=32 N(1)
and
T1T2=mArAω2=1×1×(4)2=16 N(2)
Adding (1) and (2),
T1=48 N
T1T2=4832=32

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