Two balls of masses 1kg each are attached with two strings each of length 1m as shown in figure. They are rotated in a horizontal circle with angular speed ω=4rad/s about point 'O'. The ratio of tensions T1T2 is:
A
32
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B
23
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C
4
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D
14
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Solution
The correct option is A32 Given mA=1kg;mB=1kg rA=length ofmAfrom 'O'=1m rB=length ofmBfrom 'O'′=2m
FBD considering only horizontal forces, because vertical forces balance each other i.e N=mg:
Applying equation of circular motion along radial direction for mB and mA respectively: T2=mBrBω2=1×2×42=32N−(1) and T1−T2=mArAω2=1×1×(4)2=16N−(2) Adding (1) and (2), T1=48N ∴T1T2=4832=32