Two balls of masses 2kg and 4kg are moved towards each other with velocities 4m/s and 2m/s respectively on a frictionless surface. The impulse of maximum deformation for the ball of 4kg mass is (in N−s)
A
8.00
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
8.0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
Linear momentum is conserved for the system
Let v be the common velocity during maximum deformation.
Applying linear momentum conservation equation : m1u1+m2u2=(m1+m2)v v=(m1u1+m2u2)(m1+m2)=2×4+4×(−2)2+4 v=0m/s
Impulse of deformation JD= change in momentum of any one body during deformation
For 4kg,JD=m2(v−u2) =4(0−(−2))=8N-s