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Standard XI

Physics

Why Gravitational Field

Two balls of ...

Question

Two balls of masses $m_{1} and m_{2}$ ( $m_{2} >> m_{1}$ ) are moving with initial velocities $v_{1} and v_{2}$ respectively towards each other. The final velocity of $m_{2}$ after collision will be [Assume collision to be perfectly elastic]

v_{1} + v_{2}

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v_{1}

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v_{2}

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Data insufficient

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Solution

The correct option is C $v_{2}$
Since, collision is perfectly elastic and $m_{2} >> m_{1}$ ,
$m_{2}$ will continue its motion, with the same velocity.
So, velocity of $m_{2}$ after collision $= v_{2}$

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Two balls of masses m1 and m2 (m2>>m1) are moving with initial velocities v1 and v2 respectively towards each other. The final velocity of m2 after collision will be [Assume collision to be perfectly elastic]

The correct option is C v2Since, collision is perfectly elastic and m2>>m1, m2 will continue its motion, with the same velocity. So, velocity of m2 after collision =v2

Two balls of masses $m_{1} and m_{2}$ ( $m_{2} >> m_{1}$ ) are moving with initial velocities $v_{1} and v_{2}$ respectively towards each other. The final velocity of $m_{2}$ after collision will be [Assume collision to be perfectly elastic]

The correct option is C $v_{2}$
Since, collision is perfectly elastic and $m_{2} >> m_{1}$ ,
$m_{2}$ will continue its motion, with the same velocity.
So, velocity of $m_{2}$ after collision $= v_{2}$