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Question

Two balls of same mass are dropped from the same height h, on to the floor. The first ball bounces to a height h/4 after the collision and the second ball into a height h/16. The impulse applied by the first and second ball on the floor are I1 and I2 respectively. Then

A
5I1=6I2
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B
6I1=5I2
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C
I1=2I2
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D
2I1=I2
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Solution

The correct option is A 5I1=6I2
For first ball;
Vi=2gh

Vf=2gh4=Vi4×2

Pi=mivi

Pf=mivi4=Pi4×2

PfPiΔt×Δt=Impulse

I1=32mivi

For second ball;

Pi=mivi

Pf=mivi4

PfPi=54mivi=I2

So, I1I2=3254

5I1=6I2

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