Question

Two bar magnets with magnetic moments 2M and M are fastened together at right angles to each other at their centers to from a crossed system, which can rotate freely about a vertical axis in earth's magnetic field with magnet having magnetic moment 2 M making an angle $\Theta$ with the magnetic meridian such that

• A. $\Theta =ta{n}^{-1}\left(\frac{1}{\sqrt{2}}\right)$
• B. $\Theta =ta{n}^{-1}\sqrt{3}$
• C. $\Theta =ta{n}^{-1}\left(\frac{1}{2}\right)$
  
• D. none

Answer 1

The correct option is C $\Theta =ta{n}^{-1}\left(\frac{1}{2}\right)$

$Given:$ Two bar magnets with magnetic moments $2M$ and $M$ are fastenend together at right angles to each other at their centres to form a crossed system. ; Angle= $\theta$

$Solution:$

$T\mathrm{an}\theta =\frac{M}{2M}=\frac{1}{2}$

$\theta =T{\mathrm{an}}^{-1}\left(\frac{1}{2}\right)$

$So,the$ $correct$ $option:C$