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Question

Two batteries A and B each of emf 2 volt are connected in series to external resistance R=1Ω. Internal resistance of A and B are 1.9Ω and 0.9Ω respectively. What is the potential difference between the terminals of battery A ?

A
2 V
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B
3.8 V
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C
0
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D
None of these
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Solution

The correct option is C 0
i=E1+E2R+r1+r2=2+21+1.9+0.9=43.8. Hence VA=EAirA=243.81.9=0

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