Two batteries A and B each of emf 2 volt are connected in series to external resistanceR=1Ω. Internal resistance of A and B are 1.9Ω and 0.9Ω respectively. What is the potential difference between the terminals of battery A ?
A
2 V
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B
3.8 V
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C
0
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D
None of these
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Solution
The correct option is C0 i=E1+E2R+r1+r2=2+21+1.9+0.9=43.8. Hence VA=EA−irA=2−43.81.9=0