Two bills of Rs 6075 and Rs 8505 respectively are to be paid separately by cheque of same amount. Find the largest possible amount of each cheque.
A
1230
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B
1215
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C
1118
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D
1020
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Solution
The correct option is B1215 Largest possible amount of cheque will be the HCF(6075,8505). Applying Euclid's division lemma to 8505 and 6075, we have 8505=6075×1+2430 Since, remainder 2430≠0 again applying division lemma to 6075 and 2430 6075=2430×2+1215 Again remainder 1215≠0 So, again applying the division lemma to 2430 and 1215 2430=1215×2+0 Here the remainder is zero
So, HCF=1215 Therefore, the largest possible amount of each cheque will be 1215.