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Question

Two bills of Rs 6075 and Rs 8505 respectively are to be paid separately by cheque of same amount. Find the largest possible amount of each cheque.

A
1230
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B
1215
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C
1118
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D
1020
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Solution

The correct option is B 1215
Largest possible amount of cheque will be the HCF(6075,8505).
Applying Euclid's division lemma to 8505 and 6075, we have 8505=6075×1+2430
Since, remainder 24300 again applying division lemma to 6075 and 2430
6075=2430×2+1215
Again remainder 12150
So, again applying the division lemma to 2430 and 1215
2430=1215×2+0
Here the remainder is zero
So, HCF=1215
Therefore, the largest possible amount of each cheque will be 1215.

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