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Byju's Answer

Standard IX

Physics

Universal Law of Gravitation

Two block of ...

Question

Two block of mass $m_{1}$ and $m_{2}$ are kept apart d from each other. What happen to the magnitude of the force on $m_{1}$ if the mass of $m_{2}$ is doubled?

It is quadrupled

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It is doubled

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It remain the same

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It is halved

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It is quartered

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Solution

The correct option is D It is doubled
Initial force on $m_{1}$ due to $m_{2}$ , $F = \frac{G m_{1} m_{2}}{d^{2}}$
Now the mass of $m_{2}$ is doubled keeping all the parameters same i.e $m_{2}^{'} = 2 m_{2}$
Thus new force on $m_{1}$ $F^{'} = \frac{G m_{1} (2 m_{2})}{d^{2}} = 2 F$
Thus the force also gets doubled.

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Two block of mass m1 and m2 are kept apart d from each other. What happen to the magnitude of the force on m1 if the mass of m2 is doubled?

The correct option is D It is doubledInitial force on m1 due to m2, F=Gm1m2d2Now the mass of m2 is doubled keeping all the parameters same i.e m′2=2m2Thus new force on m1 F′=Gm1(2m2)d2=2FThus the force also gets doubled.

Two block of mass $m_{1}$ and $m_{2}$ are kept apart d from each other. What happen to the magnitude of the force on $m_{1}$ if the mass of $m_{2}$ is doubled?