Two blocks A and B are placed one over the other on a smooth horizontal surface. The maximum horizontal force that can be applied on the upper block B, so that A and B move without separation is 49N. The coefficient of friction between A and B is:
A
0.2
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B
0.3
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C
0.5
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D
0.8
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Solution
The correct option is C0.5 Given, F=49N,MA=7kg,MB=3kg,μ=? Equation of motion of two blocks-system Fmax=μ(MA+MB)⋅g μ=F(MA+MB)⋅g =49(7+3)⋅9⋅8 =4910×98 =0.5.