Two blocks A and B float in water- If block A floats with 14 th of its volume immersed and block B floats with 35 th of its volume immersed- the ratio of their densities is -

The correct option is D 5 :12 Balancing the forces on the block gives, Vdg=V_immρ g f=V_immV=dρ Thus for the two blocks, f_1f_2=d_1d_2=1/43/5 ...

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Standard VIII

Physics

Buoyant Force

Two blocks A ...

Question

Two blocks A and B float in water. If block A floats with $\frac{1}{4}$ th of its volume immersed and block B floats with $\frac{3}{5}$ th of its volume immersed, the ratio of their densities is :

5 : 12

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12 : 5

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3 : 20

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20 : 3

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Solution

The correct option is D $5 : 12$
Balancing the forces on the block gives,
$V d g = V_{i m m} ρ g$
$⟹ f = \frac{V_{i m m}}{V} = \frac{d}{ρ}$
Thus for the two blocks, $\frac{f_{1}}{f_{2}} = \frac{d_{1}}{d_{2}} = \frac{1 / 4}{3 / 5} = \frac{5}{12}$

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Two blocks A and B float in water. If block A floats with14 th of its volume immersed and block B floats with 35 th of its volume immersed, the ratio of their densities is :

The correct option is D 5:12Balancing the forces on the block gives,Vdg=Vimmρg⟹f=VimmV=dρThus for the two blocks,f1f2=d1d2=1/43/5=512

Two blocks A and B float in water. If block A floats with $\frac{1}{4}$ th of its volume immersed and block B floats with $\frac{3}{5}$ th of its volume immersed, the ratio of their densities is :

The correct option is D $5 : 12$
Balancing the forces on the block gives,
$V d g = V_{i m m} ρ g$
$⟹ f = \frac{V_{i m m}}{V} = \frac{d}{ρ}$
Thus for the two blocks, $\frac{f_{1}}{f_{2}} = \frac{d_{1}}{d_{2}} = \frac{1 / 4}{3 / 5} = \frac{5}{12}$