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Question

# Two blocks A and B of equal mass m are connected through a massless string and arranged as shown in figure. Friction is absent everywhere. When the system is released from rest.

A
tension in string is mg2
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B
tension in string is mg4
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C
acceleration of A is g2
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D
acceleration in the string is 3g4
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Solution

## The correct option is B tension in string is mg4A & B have equal mass =mGiven friction is absent every whereNow making FBD except fixed wedge Let the system move with acceleration a after releasing (Ref. image 1)NowFor A (Ref. image 2)T+mgsin30o=ma ...(ii)For BMg−T=ma ...(i)From (i) & (ii)mg−T=T+mgsin30o2T=mg−mg2T=mg4From (1)mg−T=mamg−mg4=ma⇒a=3a4Hence tension in string is mg4Option B

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