Two blocks A and B of masses 5 kg and 4 kg respectively are connected by a light string. If a constant force of 9N is applied to 5kg block, the tension in the string is
4N
Let's assume block A has an acceleration of magnitude 'a' leftwards.
By constraint relation block B will also have an acceleration 'a' leftwards. Let's draw Free Body Diagram of A and B.
→ acceleration in leftward direction → acceleration in leftward direction
→ using 2nd law → using 2nd law
9 - T = 5a -----------------(I) T = 4a -----------------(II)
Adding (I) & (II) we get
9 = 9a
a = 1 m/s2
Substituting the value of 'a' in equation (II)
T = 4N