Two blocks A and B of masses m & 2m placed on smooth horizontal surface are connect with a light spring. The two blocks are given velocities as shown when spring is at natural length. Find maximum extension in the spring.
A
√2mkv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√4mkv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
√6mkv
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
√mkv
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C√6mkv Given that, m1=m m2=2m Reduced mass of the system. μ=m1m2m1+m2 ⇒μ=m×2mm+2m ⇒μ=2m3
External force on the system is zero. So energy of the system is conserved. Let maximum extension in the string is x. 12μv2r=12kx2 ⇒12×2m3(3v)2=12kx2 ⇒x=√6mkv