Two blocks A and B of masses mA=1kg and mB=2kg are placed in contact on a frictionless plane of inclination 30∘. Find the magnitude of contact force between the two blocks when an external force is applied on the blocks as shown in the figure.
A
2N
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B
6N
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C
12N
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D
10N
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Solution
The correct option is D10N We can consider both the blocks as a system of 3kg as they move same acceleration. F.B.D of the system will be
From FBD, we can write Fcos30∘−mgsin30∘=ma 20√3×√32−30×12=3a ⟹a=5m/s2 (i) Let N′ be the contact force between the two blocks. Now, FBD of 1kg block will be
From FBD, we can say N′−gsin30∘=1×a (ii) Using equation (i) in (ii), we get N′−5=5 ⟹N′=10N