Two blocks A and B of masses mA=1kg and mB=2kg are placed in contact on a frictionless plane of inclination 30∘. Find the magnitude of contact force between the two blocks when an external force is applied on the blocks as shown in the figure.
A
2N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
12N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D10N We can consider both the blocks as a system of 3kg as they move same acceleration.
F.B.D of the system will be
From FBD, we can write Fcos30∘−mgsin30∘=ma 20√3×√32−30×12=3a ⟹a=5m/s2 (i)
Let N′ be the contact force between the two blocks.
Now, FBD of 1kg block will be
From FBD, we can say N′−gsin30∘=1×a (ii)
Using equation (i) in (ii), we get N′−5=5 ⟹N′=10N