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Question

Two blocks A and B of same mass m attached with a light spring are suspended by a string as shown in the figure. Find the acceleration of block A and B just after the string is cut.

A
aA=2g(),aB=0
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B
aA=2g(),aB=g()
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C
aA=2g(),aB=g()
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D
aA=0,aB=g()
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Solution

The correct option is A aA=2g(),aB=0
When block A and B are in equilibrium position
Let spring force be T0 and tension in string be T.

FBD of B
FBD of A
When string is cut, tension T becomes zero. But spring does not change its shape after cutting. So same spring force T0 acts on mass B,

After cutting the string, FBD of B
FBD of A




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