Question

Two blocks $A$ and s of masses $100kg$ and $20kg$ respectively, separated by a distance of $5$ in are kept on a smooth surface. A mass of $60kg$ is then added to the block $A$ . Now, in order to experience same attractive force as before, the two blocks should be separated by a distance of :

Answer 1

Force is given as,

$F=\frac{G\times 100\times 20}{5^2}$

Also $F=\frac{G\times 160\times 20}{R^2}$

Equating both equations we get

$\frac{G\times 2000}{25}=\frac{G\times 3200}{R^2}$

$R^2=40$

$R=6.33in$

Now both masses will be placed $6.33in$ away from each other.