Two blocks are connected by a string as shown in the diagram. The upper block is hung by another string. A force F applied on the upper string produces an acceleration of $2 m / s^{2}$ in the upward direction in both the blocks. If T and T' be the tensions in the two parts of the string, then:

T = 84 N, T^{'} = 50 N

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T = 70 N, T^{'} = 70 N

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T = 82 N, T^{'} = 56 N

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T = 70 N, T^{'} = 60 N

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Solution

The correct option is C $T = 82 N, T^{'} = 56 N$
No right answer.

Given $A c c e l e r a t i o n = 2 m / s^{2} . F o r c e = f, m_{1} = 2 k g, m_{2} = 5 k g$

Let us assume two blocks like one.

So the equation of the motion of the combination is $f - (m_{1} + m_{2}) g = (m_{1} + m_{2}) a$

$T = (m_{1} + m_{2}) (g + a)$

By putting values.

$T = (2 + 5) (9.8 + 2) = 82.6 N$

Now consider the motion of the lower block:

$T^{'} = m_{1} g = m a \Rightarrow T^{'} = m_{1} (g + a) = 5 (9.8 + 2) = 56 N$

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